Radius of curvature of bimetallic strip? - find radius of curvature in bimetallic
Developed a temperature controller built into an environment of steam to run a bimetal is made of brass and steel at their ends by rivets. Each metal is 2.5 mm thick. At 15 ° C, the band is 10.0 cm long and straight.
Find the radius of curvature R of the Assembly to 120 ° C
Sunday, January 31, 2010
Find Radius Of Curvature In Bimetallic Radius Of Curvature Of Bimetallic Strip?
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Set L = length of the strip, df = L1-L2 in the temp. the difference, and T = thickness of a layer of metal. As he bent to the radius r is necessary that the internal-external distinction layer arc length by a difference in a radius of T is equal to dl.
ReplyDeleteThus, theta * ((R + T / 2) - (RT / 2)) = dl, where theta = L / R.
After LT / dL = r ==> r = LT / dL.
Just look for the coefficients of thermal expansion of brass and steel, take the difference and multiply by the temperature delta, the result is dL / L from there.
I found coefficients Bronze = 19E-6 / K and grades = 13E-6 / ° K.
Then dL / L = 6E-6 * 105 = 6.3e-4, r = 0.0025/6.3E-4 = 3.97 m (answer).